Here is the solution of IOE 2070 question 3(b)
# include <stdio.h>
#include <conio.h>
int main()
{
int i,j;
char word[]="pulchowk";
for(i=0;i<8;i++)
{
for(j=0;j<=i;j++)
{
if(i==3||i==5||i==7)
printf("%c",word[j]-32);
else if(i<5)
{
if(j%2==0)
printf("%c",word[j]-32);
else
printf("%c",word[j]);
}
else if(j!=0&&j%2==0)
printf("%c",word[j]-32);
else
printf("%c",word[j]);
}
printf("\n");
}
getch();
}
output of the programme:-
P
Pu
PuL
PULC
PuLcH
PULCHO
puLcHoW
PULCHOWK
/*Programme to display Nepali flag*/ # include <stdio.h> #include <stdlib.h> void main() { int i,j; for(i=1;i<=20;i++) { if(i<=8) { for(j=1;j<=8;j++) { if(j==1||i==j&&i<8) printf("* "); else if(i==8&&j>=3) printf("* "); else printf(" "); } } else if(i>8&&i<=12) { for(j=1;j<=7;j++) { if(i==12||j==1||i-j==5) printf("* "); else printf(" "); } } else if(i>12) printf("* "); printf("\n\n\n"); } }
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